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Dec 18, 2006 10:00 am |
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re: re: re: re: Riddle |
H.K.L. Sachdeva
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Dear Sumanth,
I am fully with you about Probability being a fraction between 0 & 1 because being a Mathematics Graduate myself, I fully well know that the Probability has to be a fraction of the total number of possible combinations (for a particular condition) and the total number of combinations as a whole.
But I was not talking of probability, I was talking of the possible number of combinations in which 6th, 8th & 12th house will not be occupied by any planet and that has to be a whole number.
And whether we calculate the Possible Number of Combinations or the Probability, we have to keep in mind the positioning of Rahu & Ketu which always occupy the opposite houses and for them we have to exclude them in four houses (and not three as in the case of ther planets) i.e. 2nd, 6th, 8th & 12th house.
That means, for 7 Planets we have to calculate separately and for the remaining two (counting them as one only becuase when Rahu is any of the houses 1 to 6, Ketu is in the houses 7 to 12 respectively and vice versa) we have to calculate separately. And while the exclusion for the 7 Planets is for three house, it has to be for four houses for Rahu & Ketu.
I think, it would be more appropriate to recalculate the probability or the number of combinations in the light of the foregoing.
H.K.L. Sachdeva Private Reply to H.K.L. Sachdeva (new win) |
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