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The Man in the Bar.... a riddle! | Views: 7029 |
Feb 29, 2004 1:16 pm | | The Man in the Bar.... a riddle! | # |
Kreative Quest | | A man walks into a bar and asks the barman for a glass of water. The barman pulls out a gun and points it at the man. The man says 'Thank you' and walks out. WHY??
This puzzle has claims to be the best of the genre. It is simple in its statement, absolutely baffling and yet with a completely satisfying solution. Most people struggle very hard to solve this one yet they like the answer when they hear it or have the satisfaction of figuring it out.
PM me with the answers!!!
TIME TO GET THOSE GREY CELLS WORKING......
Cheers,
Fa Ruchi.
Private Reply to Kreative Quest |
Sep 06, 2006 6:00 pm | | re: The Man in the Bar.... a riddle! | # |
FuFaji Lalit Vashishta | | Why is this still un-answered? Private Reply to FuFaji Lalit Vashishta |
Sep 06, 2006 6:13 pm | | re: re: The Man in the Bar.... a riddle! | # |
Kreative Quest | | Guess the grey cells are on a long vacation! Private Reply to Kreative Quest |
Sep 06, 2006 6:16 pm | | re: re: re: The Man in the Bar.... a riddle! | # |
Simanta Talukdar | | mine r not working right now. will try later. Private Reply to Simanta Talukdar |
Sep 06, 2006 6:31 pm | | re: The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | Not Riddle Any more
The man had hiccups. The barman recognized this from his speech and drew the gun in order to give him a shock. It worked and cured the hiccups - so the man no longer needed the waterPrivate Reply to Rajesh Pandey |
Sep 06, 2006 6:36 pm | | re: re: The Man in the Bar.... a riddle! | # |
FuFaji Lalit Vashishta | | Don give the next riddle on this thread....so whoever solevs - gives a new one Private Reply to FuFaji Lalit Vashishta |
Sep 06, 2006 6:46 pm | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Hehe Lalit, sounds like a punishment to whoever solves it :) Btw Ruchi that was amongst the classic ones in lateral thinking puzzles, just in case u didn't know.Private Reply to Mukesh Ghatiya |
Sep 06, 2006 7:09 pm | | re: re: The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | Fufaji Sir, Fantstic Idea... I take the Challenge to take this forward.
A guy living on the 20th floor in an apartment building got up early each morning to go to work in a downtown store. He always went into the elevator on the 20th floor and rode down to the entrance (1st floor). When he came home he always rode the elevator from the entrance and up to the 8th floor. He walked out of the elevator and walked the stairs up to his apartment on the 20th floor.
Private Reply to Rajesh Pandey |
Sep 06, 2006 11:33 pm | | re: re: re: The Man in the Bar.... a riddle! | # |
Sandip Kundu | | Sometimes buttons can dwarf a person :( Private Reply to Sandip Kundu |
Sep 07, 2006 12:02 am | | re: re: re: re: The Man in the Bar.... a riddle! | # |
FuFaji Lalit Vashishta | | Sandip... You are nextPrivate Reply to FuFaji Lalit Vashishta |
Sep 07, 2006 12:20 am | | re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sandip Kundu | | Lalitji, but I didnt give the answer na? :) Private Reply to Sandip Kundu |
Sep 07, 2006 12:44 am | | re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
FuFaji Lalit Vashishta | | But that was the answer, I know the PUNdit you are Private Reply to FuFaji Lalit Vashishta |
Sep 07, 2006 12:58 am | | re: re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sandip Kundu | | OK OK to avoid PUNishment...
Three people check into a hotel. They pay Rs 30 to the manager and go to their room. The manager finds out that the room rate is Rs 25 and gives Rs 5 to the bellboy to return. On the way to the room the bellboy reasons that Rs 5 would be difficult to share among three people so he pockets Rs 2 and gives Rs 1 to each person. Now each person paid Rs 10 and got back Rs 1. So they paid Rs 9 each, totaling Rs 27. The bellboy has Rs 2, totaling Rs 29.
Where is the remaining rupee? Private Reply to Sandip Kundu |
Sep 07, 2006 1:23 am | | re: re: re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | Nowhere... they paid Rs. 27, of which the fare was Rs. 25 and the bell boy pocketed Rs. 2 in tips...
cheers s
Private Reply to Sumanth Cidambi |
Sep 07, 2006 1:34 am | | re: re: re: re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sandip Kundu | | Correcto. And your prize is you get to ask the next riddle! Private Reply to Sandip Kundu |
Sep 07, 2006 2:01 am | | re: re: re: re: re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | oh, ok... here it is...
how many times on an average must an ordinary 6-sided die be thrown before every number from 1 through 6 comes up at least once?
Private Reply to Sumanth Cidambi |
Sep 07, 2006 3:58 am | | re: re: re: The Man in the Bar.... a riddle! | # |
Kedar Bedekar | | the man is a dwarf and his fingers couldnt reach higher than the 8th floor button. But then i wonder why didnt he ask for help:) Private Reply to Kedar Bedekar |
Sep 07, 2006 4:25 am | | re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | errrr, lalit, can i please mail the prize now?
Private Reply to Sumanth Cidambi |
Sep 07, 2006 10:18 am | | re: re: re: re: re: The Man in the Bar.... a riddle! | # |
FuFaji Lalit Vashishta | | Prize for what? It was Sandip Kundu who had cracked the first one. And it took me 36 minutes to realisePrivate Reply to FuFaji Lalit Vashishta |
Sep 07, 2006 11:05 am | | re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sandip Kundu | | Lalitji, I think Sumanth is referring to something else here.
And Kedar I guess replied to an earlier mail notification and hence missed the posts which had already answered the "lift" riddle...
BTW, if a puzzle gets unanswered, does it mean the person asking it, has to ask the next one as well? :(Private Reply to Sandip Kundu |
Sep 07, 2006 11:35 am | | re: re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | ya, i was not aware of the existence of this thread in the first place till i saw it this morning... the cure-for-hiccup q. is one of 24 qs, including the dwarf-in-the-lift and the music-stopped-she-died q as well, part of a mensa workshop on lateral thinking
do i take it the earlier q. on the dice is unanswered or do i wait a while?
lalit, sandeep is right on his first observation... do i mail the prize now?Private Reply to Sumanth Cidambi |
Sep 07, 2006 11:45 am | | re: The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | is there any clue in the mail?? Private Reply to Rajesh Pandey |
Sep 07, 2006 11:46 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Now I doubt if Sandip and Sumanth are talking on same lines. e.g. Sandip mentioned Kedar responding to earlier mail and Sumanth is sayin "yes I...."
hehe..confusion confusion..Private Reply to Mukesh Ghatiya |
Sep 07, 2006 11:51 am | | re: re: The Man in the Bar.... a riddle! | # |
Sandip Kundu | | Ok, the last unsolved riddle is:
"how many times on an average must an ordinary 6-sided die be thrown before every number from 1 through 6 comes up at least once?"
6x6 = 36? Private Reply to Sandip Kundu |
Sep 07, 2006 11:54 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | I was thinking same. 36 seems to be intuitive answer. Haven't formed theory yet. Private Reply to Mukesh Ghatiya |
Sep 07, 2006 12:03 pm | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | nope... not 36... cheers s
Private Reply to Sumanth Cidambi |
Sep 07, 2006 12:15 pm | | re: re: re: The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | Its a question of probability. I guess it should be 6 rasied to power of 6... 6X6X6X6X6X6 = 46656 Private Reply to Rajesh Pandey |
Sep 07, 2006 12:26 pm | | re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | nope... cheers s
Private Reply to Sumanth Cidambi |
Sep 07, 2006 1:03 pm | | re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | two more tries and then we'll move on... have another interesting lateral one as well... Private Reply to Sumanth Cidambi |
Sep 07, 2006 4:43 pm | | re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Basab Ghosh | | Factorial 6? Private Reply to Basab Ghosh |
Sep 08, 2006 1:21 am | | re: re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | No... The answer is 14.7 times... Its additive probabilities because the events are not mutually exclusive...
1 + 6/5 + 6/4 + 2 + 3 + 6...
OK, here's the next one, its easy...
My wife and I were recently shopping at a New York mall when we found ourselves on the second floor. We had a bunch of packages with us and wanted to take the lift down. The lift was on the third floor when we got to the landing. I pressed the button but the lift did not stop at our floor and went to the first floor instead. I thought it must have been mechanical and waited. On its way up, the lift went to the fourth floor and then started coming down again but did not stop at our floor and went to the first floor again. On the way up, it went to the fifth floor. I was quite irritated by then and wanted to walk down lugging all our purchases. My wife told me to wait. She predicted the lift would go to the nineth floor and then stop at our floor. She was right!!!
How did she know?
Cheers S
Private Reply to Sumanth Cidambi |
Sep 08, 2006 5:38 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Hey could u explain that "1 + 6/5 + 6/4 + 2 + 3 + 6..." to me?
And about the lift: I hope it was not 2nd floor written in Roman :D
Q1: No "Non Stop" button funda? Q2: Is New York Mall important? Q3: Could it happen in usual indian lifts too?Private Reply to Mukesh Ghatiya |
Sep 08, 2006 6:00 am | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | Mukesh
The probabilities are not mutually exclusive hence 6/1 + 6/2 +6/3 +6/4 +6/5 +6/6 which is 14.7 times...
As for the most recent riddle, none of the questions you have posed are required to solve the riddle...
Best S
Private Reply to Sumanth Cidambi |
Sep 11, 2006 6:22 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Beats me. Private Reply to Mukesh Ghatiya |
Sep 11, 2006 6:28 am | | re: re: The Man in the Bar.... a riddle! | # |
Sandip Kundu | | Give some hint... Private Reply to Sandip Kundu |
Sep 11, 2006 6:46 am | | re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | the infinite decimal...
and that makes it too easy...Private Reply to Sumanth Cidambi |
Sep 11, 2006 8:27 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Ok I was discussing with a friend of mine and he happened to point that these are the initial digits of value of pi.
If that's the correct answer, I don't think it was a lateral thinking puzzle.Private Reply to Mukesh Ghatiya |
Sep 11, 2006 8:38 am | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | Mukesh
The answer is right, the lift travelled in the sequence of the digits of pi... Complement your "friend" from me...
Your turn to pose a riddle...Private Reply to Sumanth Cidambi |
Sep 11, 2006 8:54 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Ok its a lateral thinking one.
A guy is going in a car. He switches on the radio and then kills himself.
PS:Incidentally this puzzle was given to me by the same friend who cracked the pi wala puzzle. So in a way puzzle is coming from who solved it..hehPrivate Reply to Mukesh Ghatiya |
Sep 11, 2006 9:03 am | | re: re: The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | May be he heard some terrible announcement on the radio - something like police had found who robbed the bank etc.. Private Reply to Rajesh Pandey |
Sep 11, 2006 9:04 am | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | dj kills someone using his work as an alibi... when he turns on radio, the song he had left playing is skipping... he finds out that he is caught out and decides to kill himself... Private Reply to Sumanth Cidambi |
Sep 11, 2006 9:07 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | I hate to be answered so soon Sumanth :( Rajesh u were on right track too.
And Sumanth, u give the prize to urself now..hehPrivate Reply to Mukesh Ghatiya |
Sep 11, 2006 9:25 am | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | hey, i am passing my turn... cannot be one sided... any other lateral/logic/out of the box puzzles from others...
cheers s
Private Reply to Sumanth Cidambi |
Sep 12, 2006 11:38 am | | re: re: re: The Man in the Bar.... a riddle! | # |
Nilesh | | It's an easy one...A London hairdresser recently said that he would rather cut the hair of three Indians than one Londoner. Why? Private Reply to Nilesh |
Sep 12, 2006 2:25 pm | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Because he'll get more money by from 3 hair cuts Private Reply to Mukesh Ghatiya |
Sep 12, 2006 4:07 pm | | re: re: The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | Its a Barber for women... and Indian Women have longer hair! SO more money... :D Private Reply to Rajesh Pandey |
Sep 12, 2006 4:43 pm | | re: re: re: The Man in the Bar.... a riddle! | # |
Sandip Kundu | | Or maybe the Londoner is bald Private Reply to Sandip Kundu |
Sep 12, 2006 5:03 pm | | re: re: re: re: The Man in the Bar.... a riddle! | # |
Kreative Quest | | ok so whtz the answer Nilesh or are one of the options given the answer??
Must say..... slow and steady wins the race but this mail was reaaaaaaaalllllllllllllll slow to take off....... in fact had even forgotten abt posting it here!!!!Private Reply to Kreative Quest |
Sep 13, 2006 4:23 am | | re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Vik Kac | | Hey Sumanth..... You great at this stuff....you should be an Astrologer or a Trader maybe!
I have a question.....
In astrology there are 12 houses and nine planets..... What are the chances that 3 specific houses (6th, 8th and 12th) have no planet in them...?
Vaibhav
Ps....My intutive answer to the dice thing was 18 cause out of every 3 rolls there is an average chance that you will get each number (1to6) once..... so 3*6 would be 18.....but I didnt take into account the non inclusive factor.....Private Reply to Vik Kac |
Sep 13, 2006 5:22 am | | re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | I am solving as follows:
12 houses, 9 planets, Houses 6, 8 and 12 to have no planets.
P(Houses 6, 8 and 12 having Planet 1) = 1/12 +1/12 +1/12 =3/12 or 1/4, because the events are mutually exclusive and P1 can be in H6 or H8 or H12 but not in all three houses at the same time. Therefore, the aliter probability is (1 - 1/4) = 3/4 or 0.75
Similarly, we get probability of 3/4 for P2 through P9 in Houses H1 through H12.
Now the fact that P1 is not in House 6 or in House 8 or in House 12 no way affects the behaviour of P2 through P9, i.e. the location of the planets in any house are mutually independent of each other
Hence the probability of their occurence is as follows:
3/4 x 3/4 x 3/4 x 3/4 x 3/4 x 3/4 x 3/4 x 3/4 x 3/4 or
3/4 ^ 9 or 0.07508
If wrong, do educate me.
Cheers S
Private Reply to Sumanth Cidambi |
Sep 14, 2006 2:40 pm | | The Man in the Bar.... a riddle! | # |
Shridhar | | Hi,
Try this Lateral thinking question.
callcallPrivate Reply to Shridhar |
Sep 14, 2006 3:21 pm | | re: The Man in the Bar.... a riddle! | # |
ami.de.france | | calling twice? Private Reply to ami.de.france |
Sep 14, 2006 3:24 pm | | re: re: The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | Hey, someone drive this whole thread yaar.. its going dead.. MR. SC. Will you please. Private Reply to Rajesh Pandey |
Sep 14, 2006 8:18 pm | | re: re: re: The Man in the Bar.... a riddle! | # |
FuFaji Lalit Vashishta | | I can see SC is in demand while the fench revolution will start soon
Lets hear from SCPrivate Reply to FuFaji Lalit Vashishta |
Sep 15, 2006 2:08 am | | re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | the budding astrologer needs to let us know if i got my math right first, those are the rules?
in response to the question of probabilities of stars in houses...
cheers s
Private Reply to Sumanth Cidambi |
Sep 15, 2006 4:59 am | | re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Shridhar | | Its close call Private Reply to Shridhar |
Sep 15, 2006 9:10 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | I would say that should be 're-call' :)
And about that house/planet thing, can someone tell me more about characteristics of houses and planets? e.g. Can more than one planets be in one house etc.Private Reply to Mukesh Ghatiya |
Sep 15, 2006 9:39 am | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | mukesh, wrong thread...
there's some dr. jyotish maharaj lurking somewhere in fufa (i think he spoke about the insignificance of pluto in indian astro charts a while ago) and then we have vik kac, who i overtly presume is doing his undergrad in that field and is giving us the benefits of his education as well through the popular astrology 101 online education series ;-)
am still waiting to know if my answer to the planets in houses riddle was correct... it was more probability by the way and not lateral thought...
in any event, vik kac, please let us know if my answer is right and don de la mancha, sanchez and the rest of us can get on with our riddling or we'll have to get on rocinante and our donkeys and go windmill fighting into the sunsets...
lalit, did you mean fench as in he fenched her?
cheers s
Private Reply to Sumanth Cidambi |
Sep 15, 2006 9:48 am | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Ah well Sumanth, probably u can urself tell me the answers. I needed those answers to solve the problem. So I assume u have answers already as u have a solution up there :) Private Reply to Mukesh Ghatiya |
Sep 15, 2006 10:31 am | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | errrr... lalit, can i send the prize to him now?
mukesh dude, this conversation of ours is probably not doing anything fruitful for this thread in terms of providing both entertainment and intellectual stimulation, so...
here's my next riddle for you...
Correct the following equation by FREELY moving the given four digits but without adding any mathematical symbols
26 = 47
Cheers SPrivate Reply to Sumanth Cidambi |
Sep 15, 2006 11:25 am | | re: re: re: The Man in the Bar.... a riddle! | # |
Swetha Iyer | | 49 = 72
Explanation - 6 inverted to 9 [Free to move is the key] 7 squared 2 = 49
Private Reply to Swetha Iyer |
Sep 15, 2006 11:33 am | | re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | fantastic swetha.... your turn to ding the board...
Private Reply to Sumanth Cidambi |
Sep 15, 2006 12:35 pm | | re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Swetha Iyer | | Let me ask a relatively easy one. No Instructions required. Answer is self explanatory.
HARD+HOKY=LOLY HOKY+CIA=PYKYL
Good LuckPrivate Reply to Swetha Iyer |
Sep 15, 2006 5:38 pm | | re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Lavanya Karalkar | | Swetha Iyer..If this is easy one, then what can be a hard one? Private Reply to Lavanya Karalkar |
Sep 15, 2006 5:47 pm | | re: The Man in the Bar.... a riddle! | # |
Mukesh Ghatiya | | Mine ;)
Btw I don't like these kind of puzzles where some letters r some digits and all. So boring :(Private Reply to Mukesh Ghatiya |
Sep 16, 2006 4:29 am | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | solved it.... whew, thought my saturday was going to be washed out...
i first wrote the numerals 1 through 10 in letter form... then compared the commonalities of the letters...
(what) plus (what) = loly (what) plus (what) = pykyl
comparing the alphabets in the numerals to the alphabets in the solution, i.e. what numeral starts with (l) and what numeral ends with (l), the only answer was L=N as a code.
therefore solving we come up with loly = nine and pykyl = seven
then transposing and solving for hard and hoky, we get
four + five = nine five + two = seven
the clue for cia was redundant, once you solved for hard and hoky...
cheers sPrivate Reply to Sumanth Cidambi |
Sep 16, 2006 5:30 am | | re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | which is the odd one out?
telephone limousine freighter driftwood
Private Reply to Sumanth Cidambi |
Sep 16, 2006 6:42 am | | re: re: re: re: The Man in the Bar.... a riddle! | # |
Basab Ghosh | | freighter
Doesn't have the vowel 'o' in it.Private Reply to Basab Ghosh |
Sep 16, 2006 7:27 am | | re: re: re: re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | one possible solution but not the one i was looking for...
try again...
Private Reply to Sumanth Cidambi |
Sep 16, 2006 1:49 pm | | re: The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | Limousine.
Other three have a wire / rope attached to it???Private Reply to Rajesh Pandey |
Sep 16, 2006 1:56 pm | | re: re: The Man in the Bar.... a riddle! | # |
Sumanth Cidambi | | the answer is right but the reasoning is wrong...
all the others have a number in them...
teleph ONE drif TWO ood fr EIGHT er
your turn senor la mancha!!!
cheers s
Private Reply to Sumanth Cidambi |
Sep 16, 2006 4:09 pm | | re: re: re: The Man in the Bar.... a riddle! | # |
Swetha Iyer | | Awesome Sumanth. And Lavanyaji when one knows the answer everything looks easy. ;) apologies. Private Reply to Swetha Iyer |
Sep 16, 2006 4:22 pm | | re: re: re: re: The Man in the Bar.... a riddle! | # |
Lavanya Karalkar | | yes Swetha Iyer..the trick is when you know the answer.. Private Reply to Lavanya Karalkar |
Sep 16, 2006 6:53 pm | | re: Cross out | # |
RAJAN ADVANI | | Cross out any unused letters to leave a meaningful sentence:
AAMNEYAUNNIUNSGEFDULLESTETNETRESNCE ?
Private Reply to RAJAN ADVANI |
Sep 17, 2006 2:41 am | | re: re: Cross out | # |
Sandip Kundu | | The answer is in the question:
"A MEANINGFUL SENTENCE?" (Though a question rather than a statement) Private Reply to Sandip Kundu |
Sep 17, 2006 12:54 pm | | re: re: re: Cross out | # |
Sumanth Cidambi | | next one...
what is 2520 ?Private Reply to Sumanth Cidambi |
Sep 17, 2006 1:24 pm | | re: Cross out | # |
Rajesh Pandey | | Its the lowest number which gives a whole number when divided by all numbers from 1 to 10...
2520/1 = 2520 2520/2 = 1260 2520/3 = 840 ... 2520/10 = 252
That was more of a trivia SC, but fun trying to remember it!!
Another riddle...
A mother has three sick children. She has a 24-ounce bottle of medicine and needs to give each child eight ounces of the medicine. She is unable to get to the store and has only three clean containers, which measure 5, 11 and 13 ounces. The electricity is out and she has no way of heating water to wash the containers and doesn't want to spread germs. How can she divide the medicine to give each child an equal portion without having any two children drink from the same container?Private Reply to Rajesh Pandey |
Sep 17, 2006 5:00 pm | | re: re: Cross out | # |
Basab Ghosh | | 1. She fills the 13 oz container from the 24 oz one 2. She fills the 5 oz container from the 13 oz container, leaving 8 oz in it. She empties the 8 oz into the 11 oz container. 3. She empties the 5 oz container into the 24 oz container, which now holds 16 oz of medicine. She fills the 13 oz container from the 24 oz container and then fills the 5 oz container from the 13 oz container. The 13 oz container now has 8 oz of medicine in it. 4. She empties the 5 oz container into the 24 oz container. The three containers 11 oz, 13 oz and 24 oz all contain 8 oz of medicine now.
NOW DON'T TELL ME THIS IS A POSSIBLE ANSWER, BUT YOU HAD SOMETHING ELSE IN MIND. I CAN'T COMPENSATE FOR ANYONE'S LACK OF IMAGINATION.
Private Reply to Basab Ghosh |
Sep 17, 2006 5:11 pm | | re: re: re: Cross out | # |
Lavanya Karalkar | | Great Basab Ghosh..this is one way of rational thinking. I may have a different way and others may have other different ways. Anyhow mother's problem solved na? Private Reply to Lavanya Karalkar |
Sep 17, 2006 5:15 pm | | re: re: re: Cross out | # |
Rajesh Pandey | | Nothing sir..
your turn to put up a riddlePrivate Reply to Rajesh Pandey |
Sep 17, 2006 5:19 pm | | re: re: Cross out | # |
Swetha Iyer | | Sol 1 - We have here -
5oz container ; 11oz container ; 13oz container Fill containers in foll fashion - 5c 11c 13c 5 11 0
24 - 16 = 8 ounces remains in medicine bottle. Administer first dose to one child
Add 11c to 13c Add remaining from 5c to 13c 3oz remains in 5c Add remaining from 5c to 11c
Status now -
5c 13c 11c 0 13 3
Now fill 5c from 13c So 13-5 = 8 Administer second dose to another one
5c + 11c = [5oz + 3oz] = 8 oz Give the remaining medicine to the last child.
Sol 2. - Wait for the power :)Private Reply to Swetha Iyer |
Sep 17, 2006 5:23 pm | | re: re: re: Cross out | # |
Rajesh Pandey | | Nothing sir.. You are absolutely right!!
your turn to put up a riddle Private Reply to Rajesh Pandey |
Sep 17, 2006 5:29 pm | | re: re: re: re: Cross out | # |
Basab Ghosh | | How did the mother distinguish between the 13 oz and 11 oz bottles in the dark?
This is the riddle..... give free flight to your imagination!Private Reply to Basab Ghosh |
Sep 17, 2006 5:45 pm | | re: re: re: re: re: Cross out | # |
Lavanya Karalkar | | Basab Ghosh.. you have imagined too much. Who said it was dark? It is said, the electricity was out and she is unable to heat water to clean the containers. Even if it had been night as Basab Ghosh wants to believe, then
Height of the containers could have been the indicator na?
Mother's intuition would have greatly helped in solving the problem na?
Private Reply to Lavanya Karalkar |
Sep 18, 2006 4:09 am | | re: re: re: re: re: re: Cross out | # |
Vik Kac | | Sumanth Hi,
Hadnt logged onto for a bit..... Some research at my end indicates that the answer would be 12C3 which is 12*11*10/3*2*1 = 1/220 ....
Private Reply to Vik Kac |
Sep 18, 2006 4:48 am | | re: re: re: re: re: re: re: Cross out | # |
Sumanth Cidambi | | hey vaibhav
could you PM me the logic please for your solution... i could not figure how you arrived at that probability...
also if you meant 12C3, it is a figure > 1 and that is improbable...
i also saw a new riddle solved by basab, already... aaah well, will await the next one...
Private Reply to Sumanth Cidambi |
Sep 18, 2006 8:47 am | | re: Cross out | # |
Rajesh Pandey | | A rich man's son was kidnapped. The ransom note told him to bring a valuable diamond to a phone booth in the middle of a public park. Plainclothes police officers surrounded the park, intending to follow the criminal or his messenger. The rich man arrived at the phone booth and followed instructions but the police were powerless to prevent the diamond from leaving the park and reaching the crafty villain. What did he do? Private Reply to Rajesh Pandey |
Sep 18, 2006 9:20 am | | re: re: Cross out | # |
Sumanth Cidambi | | trained pigeon in booth, carries diamond to villain, police cannot fly... Private Reply to Sumanth Cidambi |
Sep 18, 2006 9:30 am | | re: re: re: Cross out | # |
Rajesh Pandey | | Aboslutely right Sumanth... the villain had put a pigeon in the booth with a note saying he has to put the diamond. Its a real crime story that took place in Thailand or Taiwan or somewhere...
Your turn SC.. take the thread aheadPrivate Reply to Rajesh Pandey |
Sep 18, 2006 10:23 am | | re: re: re: re: Cross out | # |
Sumanth Cidambi | | art imitating life imitating art eh...hmmm, interesting...
ok, my riddle...
Which of the following nonsense sentences is the odd one out.
1. more solo goals 2. lame animal pairs 3. only some sail 4. plaza mail louse
cheers s
Private Reply to Sumanth Cidambi |
Sep 18, 2006 12:47 pm | | re: re: Cross out | # |
Rajesh Pandey | | Any clues - Is it got something to do with Words / Letters?? Private Reply to Rajesh Pandey |
Sep 18, 2006 12:59 pm | | re: re: re: Cross out | # |
Sumanth Cidambi | | Miracles will have their claimers More will bow to rome He and she are in the house But there's only me at home
Private Reply to Sumanth Cidambi |
Sep 27, 2006 11:39 am | | re: re: re: re: re: Cross out | # |
Rajesh Pandey | | Is it only some sail... the other three seem to be land based, while sailing is sea based! Private Reply to Rajesh Pandey |
Sep 27, 2006 11:56 am | | re: re: re: re: re: re: Cross out | # |
Sumanth Cidambi | | right answer but wrong logic... words in 1, 2 and 4 are all acronyms for capital cities...
don, a la derek, 1/2 a point for that... your turn to riddle...
cheers s
Private Reply to Sumanth Cidambi |
Sep 27, 2006 12:46 pm | | re: re: re: re: re: re: re: Cross out | # |
Rajesh Pandey | | Chalo,
Aadha point he sahi.. gadi to aagay badhi!
A vacationing family sitting around the campfire has the following conversation: 1. Father: What day is it? I am sure it isn't Tuesday, Wednesday or Thursday. 2. Mother: Well that's not very helpful dear. Besides yesterday was Friday. 3. Father: No, now that I think about it, yesterday wasn't Friday, tomorrow is Friday. 4. Junior: The day after tomorrow is Thursday. 5. Susie: You are nuts. Tomorrow is Thursday. 6. Mother: Actually, it's probably Thursday today. 7. Junior: All we know for sure is that it wasn't Sunday yesterday. If only one statement above is true, what day of the week is it?
Private Reply to Rajesh Pandey |
Sep 27, 2006 1:22 pm | | re: re: re: re: re: re: re: re: Cross out | # |
Sandip Kundu | | Monday... Private Reply to Sandip Kundu |
Sep 27, 2006 1:36 pm | | re: re: re: re: re: re: re: re: re: Cross out | # |
Rajesh Pandey | | Sahi Zawaab Sandip...
Number each person's statement and write down the list of days that it could be according to each statement. 1. Monday, Friday, Saturday, Sunday 2. Saturday 3. Thursday 4. Tuesday 5. Wednesday 6. Thursday 7. Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday The only day mentioned one time is Monday. Therefore it must be Monday, otherwise one of the other statements would be true.
Your turn to put up the question now!! Private Reply to Rajesh Pandey |
Oct 05, 2006 5:50 pm | | re: re: re: re: re: re: re: re: re: re: Cross out | # |
Rajesh Pandey | | Where you disappeared Sandip Private Reply to Rajesh Pandey |
Oct 05, 2006 7:33 pm | | re: re: re: re: re: re: re: re: re: re: re: Cross out | # |
Kreative Quest | | You are the treasurer in charge of the Royal mint, which produces a single type coin, the grote. There are ten machines producing grotes, one machine is producing grotes weighing one gram less than they should, each coin should weigh 10 grams. You have a set of broken scales which can be fixed to provide one single weigh of a single amount (no weight changes are allowed). Using the scales once you must identify the single faulty machine.
How do you do it?
Cheers,
Fa Ruchi. Private Reply to Kreative Quest |
Oct 06, 2006 12:15 am | | Cross out | # |
SOEB FATEHI | | First name the machines A, B, C, D, E, F, G, H, I and J.
Take 1 grote from A. Take 2 grotes from B. Take 3 grotes from C. Take 4 grotes from D. Take 5 grotes from E. Take 6 grotes from F. Take 7 grotes from G. Take 8 grotes from H. Take 9 grotes from I. Take no grotes from J.
Now actually weigh the grotes.
If the weight is 450 grams then machine J is defective. If the weight is 449 grams then machine A is defective. If the weight is 448 grams then machine B is defective. If the weight is 447 grams then machine C is defective. If the weight is 446 grams then machine D is defective. If the weight is 445 grams then machine E is defective. If the weight is 444 grams then machine F is defective. If the weight is 443 grams then machine G is defective. If the weight is 442 grams then machine H is defective. If the weight is 441 grams then machine I is defective.
NOW > > > >
Let us introduce a new element into the problem to make it more grotesque!
Suppose you do not know whether there is a defective grote machine at all or not - and you do not know that the defective grote if any will be actually heavier or lighter - but you do know that the difference has to be one gram per grote if at all there is a difference - then can you still do it in one weighing?
socho . . . . socho . . . . Basab and Sumanth and Sandip se poocho . . . . finally kisi anpadh platform wasi se poocho . . . . Private Reply to SOEB FATEHI |
Oct 06, 2006 4:50 am | | re: Cross out | # |
Sandip Kundu | | Is the weighing machine digital?
Private Reply to Sandip Kundu |
Oct 06, 2006 6:25 pm | | re: re: Cross out | # |
Kreative Quest | | Well the answer is nope itz not a digital machine so think think. Basabji has given u the clue!
Private Reply to Kreative Quest |
Oct 07, 2006 2:51 am | | re: re: re: Cross out | # |
Sandip Kundu | | Where is the clue? And I guess you are asking me to think about Soeb's puzzle, not yours, since that has been already answered... Private Reply to Sandip Kundu |
Oct 07, 2006 2:01 pm | | re: Cross out | # |
Basab Ghosh | | Well, for this one, in addition to the sequence described by Soeb for Ruchi's problem, take 10 coins from machine J.
If the weight is 550 gms, then no machine is defective.
If the weight is more or less by 1 gm, then machine A is defective... and so on.
Neat solution to a grotesque problem.... :D
Private Reply to Basab Ghosh |
Oct 07, 2006 4:10 pm | | re: re: Cross out | # |
SOEB FATEHI | | Basab the algorithm remains the same but you increase the logistics that way . . . . in solutions the optimal case is the one to go for always Private Reply to SOEB FATEHI |
Oct 07, 2006 6:01 pm | | re: re: re: Cross out | # |
Lavanya Karalkar | | why not the easy sawaal like 'which came first, egg or chicken?' instead of katin katin sawal where our intellectually intellectual Soeb Fatehi, Basab Ghosh, Sandip Kundu and others like them have to use Fufa Space and their brain. Private Reply to Lavanya Karalkar |
Oct 07, 2006 6:49 pm | | re: re: re: re: Cross out | # |
Manpreet Singh Kalsey | | According to Santa and Banta - Whatever is ordered first will come first.
Private Reply to Manpreet Singh Kalsey |
Oct 07, 2006 6:56 pm | | re: re: re: re: re: Cross out | # |
Lavanya Karalkar | | wah! Wah!
Kya sawaal aur kya Jawaab !!
Riddle ho toh aisi....
ishar koi A,B,.C.D.E,F,G,H NAHI na koi 1,2,3,4,5,6, numbering.. No algorithms, No brain wprk, no reasoning.
jat poocho pat jawab. Private Reply to Lavanya Karalkar |
Oct 08, 2006 1:55 pm | | re: re: re: re: re: re: Cross out | # |
Lavanya Karalkar | |
Now for the next easy round,. Bachen log taaliyan...
now sochna shuru karen...
_______
Private Reply to Lavanya Karalkar |
Oct 08, 2006 2:07 pm | | re: re: re: re: re: re: re: Cross out | # |
SOEB FATEHI | | losing your touch? spellcheck!
that should have been thaaliyan . . . .Private Reply to SOEB FATEHI |
Oct 08, 2006 4:28 pm | | re: re: re: re: re: re: re: re: Cross out | # |
Lavanya Karalkar | | lekin in this post your job was not to spellcheck but to try to (repeat) try to solve the riddle Soeb Fatehi. idhar Old and obese ka algorythm, trignometry kuch nahi chalege. Sirf chahiye Santa Bantawala brainy brain. Private Reply to Lavanya Karalkar |
Oct 09, 2006 7:18 am | | re: re: re: re: re: re: re: re: re: Cross out | # |
Lavanya Karalkar | | Arre..ab thak koi solve nahi kar saka kya? Mr.Manpreet Singh Kalsey, Santa Banta ko bulana padega kya? Private Reply to Lavanya Karalkar |
Oct 09, 2006 11:45 am | | re: re: re: re: re: re: re: Cross out | # |
Amita | | Nobody wants to play the easy round.... sabko tough round hi khelna hai....
Private Reply to Amita |
Oct 09, 2006 12:46 pm | | re: re: re: re: re: re: re: re: Cross out | # |
SOEB FATEHI | | chalo ladies round over . . . . real men come back now Private Reply to SOEB FATEHI |
Oct 10, 2006 8:27 am | | re: re: re: re: re: re: re: re: re: Cross out | # |
Lavanya Karalkar | | solve nahi kar saka toh batha dena hum solution de denge na> why running running from problems? Private Reply to Lavanya Karalkar |
Oct 17, 2006 5:03 am | | re: re: re: re: re: re: re: re: re: re: Cross out | # |
Sandip Kundu | | Ok, a bit of googling will help solving this..
Originally hailing from Amritsar, A started his career as an assistant painter at Madan Theatres in Calcutta. He then moved on to become a still photographer with New Theaters and was soon designing posters for the company. His first stint in commissioned writing was as the dialogue writer and lyricist in B, one of the all time greatest movies of Indian Cinema starring C, the most prolific star of his times, and featuring D as the cameraman, an established director of the coming years. He introduced two of the most well known faces of Indian Cinema, E and F, in Bechara Bhagwan, which was later renamed G. Also featuring in his list of discoveries are H, E's sister in law and I, whose daughter J has been one of the most amazing actresses in recent times. He also has the unique distinction of directing K, the then Prime Minister of the country, in a movie for Children's Films Society
Identify A - K Private Reply to Sandip Kundu |
Oct 18, 2006 11:12 am | | Cross out | # |
Rajesh Pandey | | A - Kidar Nath Sharma B - Devdas C - K L Saigal D - Bimal Roy E - Raj Kapoor F - Madhubala G - NeelKamal H - Geeta Bali I - Tanuja J - Kajol K - Jawaharlal Nehru
Dont know if Neel Kamal was called Bechara Bhgavan but it was the first of Raj Kapoor & Madhubala... Nehru is just a guess since he established the CFSI! Private Reply to Rajesh Pandey |
Oct 18, 2006 1:02 pm | | re: Cross out | # |
Sandip Kundu | | I=Naseem Banu J =Saira Banu Private Reply to Sandip Kundu |
Oct 18, 2006 1:50 pm | | re: re: Cross out | # |
Rajesh Pandey | | Baki sab correct??? He did launch Tanuja though! :D
Here's an easy one
My head and tail both equal are, My middle slender as a bee. Whether I stand on head or heel Is quite the same to you or me. But if my head should be cut off, The matter's true, though passing strange Directly I to nothing change. What Am I?
Private Reply to Rajesh Pandey |
Oct 22, 2006 4:32 pm | | re: re: re: Cross out | # |
Rajesh Pandey | | Suggest look at numbers! I thought this was really easy Private Reply to Rajesh Pandey |
Oct 23, 2006 5:19 am | | re: re: re: re: Cross out | # |
Sumanth Cidambi | | its 8 man... i was waiting for some one to fill the post...
cheers s
PS: lateratus is an album by tool... Private Reply to Sumanth Cidambi |
Nov 10, 2006 8:08 pm | | Cross out | # |
Rajesh Pandey | | What about the next qiz Sumanth saab!! Private Reply to Rajesh Pandey |
Nov 11, 2006 1:18 pm | | re: Cross out | # |
Sumanth Cidambi | | An ancient king wanted to change all the high days and holidays in his kingdom. He calls his ministers and decrees that holidays will occur on the high day and on the low day of each week. These were Saturday and Friday, respectively.
If the week was in the order of the High days going down to the Low days, what would the sequence of the "new week" be?
Private Reply to Sumanth Cidambi |
Nov 16, 2006 9:56 am | | just a guess | # |
mohini poddar | | Is it...that the weekdays wud be reversed...say..saturday den friday,thursady...n so on.. Is the punishment just for giving right answers or for wrong as well???Private Reply to mohini poddar |
Nov 22, 2006 6:05 pm | | re: just a guess | # |
Sumanth Cidambi | | mohini, wrong answer... Private Reply to Sumanth Cidambi |
Nov 29, 2006 8:18 pm | | re: re: just a guess | # |
Rajesh Pandey | | any clues sumanth saab??? Private Reply to Rajesh Pandey |
Nov 30, 2006 3:46 am | | re: re: re: just a guess | # |
Sumanth Cidambi | | sum of alphabetical positions... Private Reply to Sumanth Cidambi |
Nov 30, 2006 7:09 pm | | just a guess | # |
Rajesh Pandey | | SATURDAY SUNDAY MONDAY TUESDAY WEDNESDAY THURSDAY FRIDAY
Private Reply to Rajesh Pandey |
Dec 01, 2006 5:10 pm | | re: just a guess | # |
Sumanth Cidambi | | wrong answer... Private Reply to Sumanth Cidambi |
Dec 12, 2006 5:23 pm | | re: re: just a guess | # |
Rajesh Pandey | | What then sir!! Private Reply to Rajesh Pandey |
Dec 13, 2006 2:18 am | | re: re: re: just a guess | # |
Sumanth Cidambi | | Saturday - High Day Friday - Low Day
Alphabetical sequence of the other days... hence...
Saturday Monday Sunday Thursday Tuesday Wednesday Friday
Cheers S
PS: Don, some one else's turn... Am tired of cracking me up!!!
Private Reply to Sumanth Cidambi |
Dec 15, 2006 1:59 pm | | Riddle | # |
Rajesh Pandey | | You have seen a nice shirt at The Bay , worth $97.00
You don’t have money, you borrowed $50 from your wife and $50 from your girl friend. How much is your money now? (Answer: $100.00, correct?)
You buy the shirt, how much is your change? (answer: $3.00)
You return $ 1.00 to your wife, how much more you owe your wife? (answer: $49.00)
You return $1.00 to your girlfriend, How much more you owe your girlfriend? (answer: $49.00)
The remaining $ 1.00 is with you, correct?
Now, this is the computation : $49(you owe your wife) + $49(you owe your girlfriend)? (ans. $98.00)+ $1.00 with you? (ans. $99.00),
WHERE IS THE OTHER $1.00 ?
Now, another computation :
$ 49(you owe your wife) + $1.00 the one you returned to her, equals: $50.00, Correct? $49(you owe your girlfriend) + $1.00 the one you returned to her, equals: $50.00, correct? $50.00 + $50.00 (ans. $100.00 ) plus $1.00 you keep with you, (ans. $101.00)
HOW HAS IT BECOME MORE ?
Private Reply to Rajesh Pandey |
Dec 15, 2006 6:42 pm | | re: Riddle | # |
Sumanth Cidambi | | no fair, i am a little durnk and insipred to solve this...
when you return $1 each, you ahve borrowed a net of $98, shirt costs $97, you have a $1, it balances... work the math...
the second computation is worng to start with...you owe $49 ecah after returning $1 to bith the wife and the girlfreind... so that makes it $98 and you have $1, letf over from the shirt prucahse...
dno... not at thsi csot...
cjheers s
Private Reply to Sumanth Cidambi |
Dec 18, 2006 7:55 am | | re: re: Riddle | # |
H.K.L. Sachdeva | | Going through the old ones, I find that the maximum possible number of ways the nine planets may not occupy the 6th, 8th & 12th house, has to be calculated as follows :-
1. Seven Planets (other than Rahu & Ketu) can occupy any place but Rahu and Ketu are always in the opposite house to each other.
2. For the seven Planets (other than Rahu & Ketu) not to occupy the 6th, 8th or 12th house means they can occupy any of the other nine houses, the probability of which is 9 for each planet - meaning - 63 (9 x 7).
3. Now for Rahu & Ketu, their positions if they occupy 6th, 8th or 12th houses, will be like (For Rahu) 6 - 12, 8 - 2 & 12 - 6 or the other way round (For Ketu) 12 - 6, 2 - 8 or 6 - 12 and we see that 6 - 12 & 12 - 6 combinations are repeated twice. So out of total of these six positions, we remove two and we are left with a total of four positions. Thus to calculate the probability of Rahu occupying the other eight houses (Ketu will be automatically taking the opposite house) will be 8 (8 x 1).
4. So the total number of possible combinations for none of the planets to be there in 6th, 8th & 12th houses will be 63 + 8 = 71 [out of a total of 96 (12 x 8) - taking only one set of combinations for Rahu & Ketu]. Private Reply to H.K.L. Sachdeva |
Dec 18, 2006 8:25 am | | re: re: re: Riddle | # |
Sumanth Cidambi | | dear mr. sachdeva
probability is usually a number, not necessarily whole, between zero and one...
cheers s
Private Reply to Sumanth Cidambi |
Dec 18, 2006 9:30 am | | re: re: re: re: re: Riddle | # |
Sumanth Cidambi | | errr.... i've always thought that chances means a probability is involved somewhere... as in, what are the chances that you throw three heads in five consecutive tosses of a two sided coin and so on... do correct me if my interpretation was wrong...
secondly, i am not sure how the probability is 0.74, as i worked it out to be 0.07xx... again, how did you arrive at 71/96?
cheers s
ps: am no astrologer...
Private Reply to Sumanth Cidambi |
Dec 18, 2006 10:00 am | | re: re: re: re: Riddle | # |
H.K.L. Sachdeva | | Dear Sumanth,
I am fully with you about Probability being a fraction between 0 & 1 because being a Mathematics Graduate myself, I fully well know that the Probability has to be a fraction of the total number of possible combinations (for a particular condition) and the total number of combinations as a whole.
But I was not talking of probability, I was talking of the possible number of combinations in which 6th, 8th & 12th house will not be occupied by any planet and that has to be a whole number.
And whether we calculate the Possible Number of Combinations or the Probability, we have to keep in mind the positioning of Rahu & Ketu which always occupy the opposite houses and for them we have to exclude them in four houses (and not three as in the case of ther planets) i.e. 2nd, 6th, 8th & 12th house.
That means, for 7 Planets we have to calculate separately and for the remaining two (counting them as one only becuase when Rahu is any of the houses 1 to 6, Ketu is in the houses 7 to 12 respectively and vice versa) we have to calculate separately. And while the exclusion for the 7 Planets is for three house, it has to be for four houses for Rahu & Ketu.
I think, it would be more appropriate to recalculate the probability or the number of combinations in the light of the foregoing.
H.K.L. Sachdeva Private Reply to H.K.L. Sachdeva |
Dec 18, 2006 11:57 am | | re: re: re: re: re: Riddle | # |
Sumanth Cidambi | | your penultimate paragraph read like an quantitative techniques problem that i've usually encountered...
anyways, cool... will solve for the revised problem set in line with astrological principles, more from an academic perspective than anything else
thanks again sir... :-)
cheers s
Private Reply to Sumanth Cidambi |
Dec 20, 2006 9:36 am | | re: re: re: re: re: re: Riddle | # |
H.K.L. Sachdeva | | Dear Sumanth,
I think, going by your analogy, the possible number of combinations of seven planets' (other than Rahu & Ketu) occupying nine out twelve houses will be :-
9 x 9 x 9 x 9 x 9 x 9 x 9 = 47,82,969
out of a total number of
12 x 12 x 12 x 12 x 12 x 12 x 12 = 3,58,31,808
combinations
and
the possible number of combinations for one planet (taking Rahu & Ketu as one) occupying eight out of twelve houses, singly, will be :-
8 out of 12
and when we combine it with the combinations of the other seven planets, the total number of combinations should be :-
9 x 9 x 9 x 9 x 9 x 9 x 9 x 8 = 3,82,63,752
out of a total number of
12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 = 42,99,81,696
thereby giving a probability of
0.088989.
H.K.L. Sachdeva Private Reply to H.K.L. Sachdeva |
Dec 20, 2006 9:38 am | | re: re: re: re: re: re: re: Riddle | # |
H.K.L. Sachdeva | |
Hi ! All,
This is an interesting one and a very easy one.
Here is a position "1 + 1 = 11" made with matchsticks.
You have just to reposition one of the matchsticks so as
to give the result of "130"
Private Reply to H.K.L. Sachdeva |
Dec 22, 2006 9:13 pm | | re: The Man in the Bar.... a riddle! | # |
Dhaval Roy | | The man had a bad bout of hiccups, coz of which he asked for water... only a moron wud go to a bar and not drink! when the bar tender showed him th gun, his hiccups stopped... so he said thx and left. Private Reply to Dhaval Roy |
Dec 23, 2006 5:43 am | | re: re: The Man in the Bar.... a riddle! | # |
H.K.L. Sachdeva | | Dhaval,
You are still stuck up with hiccups, hiccups are over since long.
Now the latest is to attend to the matchsticks problem. H.K.L. SachdevaPrivate Reply to H.K.L. Sachdeva |
Dec 28, 2006 3:49 pm | | The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | sir, two clarifications!!
These numbers are written in what language! Roman, English or??? secondly the symbols + and = are also made of matchsticks??Private Reply to Rajesh Pandey |
Jan 04, 2007 2:31 pm | | re: re: re: The Man in the Bar.... a riddle! | # |
dinesh thonur | | he was a midget(i knew this one) Private Reply to dinesh thonur |
Jan 04, 2007 2:37 pm | | re: re: re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
dinesh thonur | | Sandeep, The calculation is incorrect forthe simple reason that the Rs 2 that the guy kept forms part of the expenditure incurred to the occupants.So it is wrong to add it to Rs 27 which is the sum total of expenditures. So the money which was returned is to be added ie Rs 3. Private Reply to dinesh thonur |
Jan 04, 2007 2:41 pm | | re: re: re: re: re: re: re: re: re: re: re: The Man in the Bar.... a riddle! | # |
dinesh thonur | | Considering the law of probability is it 6*5*4*3*2 times? Private Reply to dinesh thonur |
Jan 04, 2007 2:54 pm | | re: Riddle | # |
dinesh thonur | | Don, this is similar to Sumeets puzzle. The calculations are incorrect. You got to add the correct amount to the money retained/returned. Private Reply to dinesh thonur |
Jan 04, 2007 3:13 pm | | A logical thinking puzzle | # |
dinesh thonur | | In a factory there are 10 machines that produce balls weighing 10 grams each. One of the machines developed a defect and started producing balls weighing 9 grams.We have a weighing machine but are permited to weigh only once.However we can weigh any number of balls but just once. How do we identify the defective machine? (the answer is straight forward and logical) Private Reply to dinesh thonur |
Jan 05, 2007 9:07 am | | re: A logical thinking puzzle | # |
Siddhartha Rathi | | Hi Dinesh,
First no. each machine as 1, 2, ,,, 10 and then take as many balls from each machine as per the no. of the machine.
Now weigh them together. the total weight will be 10+20+30+...+100 = 550 grams in reality if there would have been no error in any of the machines. If the weight comes as 549 then machine one is defective, if weight comes as 548 then machine two is defective and so on till weight comes as 540 then machine ten will be defective.
SiddharthaPrivate Reply to Siddhartha Rathi |
Jan 05, 2007 11:32 am | | re: re: A logical thinking puzzle | # |
dinesh thonur | | Great Siddhartha, thats what it is. Private Reply to dinesh thonur |
Jan 05, 2007 11:35 am | | re: re: A logical thinking puzzle | # |
dinesh thonur | | Great Siddhartha, that is what it is Private Reply to dinesh thonur |
Jan 05, 2007 11:51 am | | A Murder Mystery | # |
dinesh thonur | | A police man was patrolling a street. Once reached near a 2 storied building,he heard a cry from the first floor room facing the street. "john.. dont kill me" .Next he heard a shot being fired and a pistol came flying out of the window. (meaning to say the police man could not have found anyone in possession of the weapon).He rushed up.... and found one person lying dead and three others in the room (all strangers to him ofcourse). He was able to grab the real culprit immediately (no question,answers). By reasonable assumptions (it is fairly straight forward) what condition was fulfilled that enabled him to do so?
Hint: Of the three present one was a doctor,anathor an engineer and the third a business man.Who was the culprit?Private Reply to dinesh thonur |
Jan 05, 2007 12:53 pm | | re: A Murder Mystery | # |
Sumanth Cidambi | | two out of three were women... Private Reply to Sumanth Cidambi |
Jan 05, 2007 7:52 pm | | re: re: A Murder Mystery | # |
Rajesh Pandey | | Second Sumanth Private Reply to Rajesh Pandey |
Jan 06, 2007 1:08 pm | | re: re: re: A Murder Mystery | # |
dinesh thonur | | No Don, it was the business man.. he was the only man present other was a lady doctor and a lady engineer. Private Reply to dinesh thonur |
Jan 06, 2007 1:15 pm | | New String | # |
dinesh thonur | | Anyone interested in logical puzzles I am starting a string by that name. Also do remember to contribute. Thanks. Private Reply to dinesh thonur |
Jan 07, 2007 4:07 am | | re: New String | # |
Sumanth Cidambi | | don, looks like we cracked it, two out of three were women... whyn't you give the next one a shot...
cheers s
Private Reply to Sumanth Cidambi |
Jan 07, 2007 12:41 pm | | re: The Man in the Bar.... a riddle! | # |
H.K.L. Sachdeva | |
Don Rajesh,
These are all match sticks. As I said that the present
position indicates "| + | = ||", may be, as of now, you
can treat them to be Roman.
Now, what you have to do is to move one of the match
sticks from one place to another place so as to give the
result of "130".
H.K.L. Sachdeva Private Reply to H.K.L. Sachdeva |
Jan 08, 2007 7:55 pm | | The Man in the Bar.... a riddle! | # |
Rajesh Pandey | | Sach Saab!! I give Up...
Sorriez! Private Reply to Rajesh Pandey |
Jan 09, 2007 5:36 am | | re: The Man in the Bar.... a riddle! | # |
H.K.L. Sachdeva | |
Don Rajesh,
This was very simple.
You have just to move one match stick from one place to
another place so as to give the result of "130".
See, how ? Move one stick from "=" sign over to "+" sign,
"=" becomes "-" sign and "+" becomes "4" and the equation
becomes "141 - 11" which is equal to 130.
H.K.L. Sachdeva Private Reply to H.K.L. Sachdeva |
Jan 09, 2007 8:12 am | | The Big Test | # |
H.K.L. Sachdeva | |
THE BIG TEST
(Passing Requires Only 4
Correct Answers Out Of 10) |
THE BIG TEST
For Answers, please make a block with
your mouse in between the two #'s. |
DECIDE YOUR ANSWERS FIRST, THEN LOOK -->>
1). How long did the Hundred Years War last ?
2). Which country makes Panama hats ?
3). From which animal do we get cat gut ?
4). In which month do Russians celebrate
the October Revolution ?
5). What is a camel's hair brush made of ?
6). The Canary Islands in the Pacific are
named after what animal ?
7). What was King George VI's first name ?
8). What color is a purple finch ?
9). Where are Chinese gooseberries from ?
10). What is the color of the black box in
a commercial airplane ?
|
ANSWERS
1). # 116 years #
2). # Ecuador #
3). # Sheep and Horses #
4). # November #
5). # Squirrel Fur #
6). # Dogs #
7). # Albert #
8). # Crimson #
9). # New Zealand #
10). # Orange #
|
Private Reply to H.K.L. Sachdeva |
Jan 14, 2007 2:34 pm | | The Big Test | # |
Rajesh Pandey | | 1. Hundred Year War - 116 years 2. Panama Hats - Ecuador 3. Cat Gut - Sheep 4. October Revolution - November (took place in 1917) 5. Camel Hair Brush - Squirrel 6. Canary Island - Dogs 7. King George VI - Albert 8. Purple Finch - Crimson 9. Chinese Gooseberry - New Zealand 10. Black Box - Orange
My Question -
Why do Chinese men eat more rice than the Japanese men.
Private Reply to Rajesh Pandey |
Jan 15, 2007 3:42 am | | re: The Big Test | # |
Sumanth Cidambi | | there are more chinese men than japanese men? Private Reply to Sumanth Cidambi |
Jan 15, 2007 4:46 am | | re: re: The Big Test | # |
zohratamjeed | | Ok Sumanth...you get to ask a question again:) Private Reply to zohratamjeed |
Jan 28, 2007 3:49 pm | | The Big Test | # |
Rajesh Pandey | | Yep, Chinese have more population than Japanese, therefore more men! Private Reply to Rajesh Pandey |
May 06, 2007 5:54 pm | | re: The Man in the Bar.... a riddle! | # |
FuFaji Lalit Vashishta | | who is next? Private Reply to FuFaji Lalit Vashishta |
May 07, 2007 5:16 am | | re: re: The Man in the Bar.... a riddle! | # |
Pankaj Prakash | | Bade Fufaji, Since the Chinese are the first, the Japanese are the NEXT. Private Reply to Pankaj Prakash |
Sep 01, 2007 1:21 pm | | The Man in the Bar.... a riddle! | # |
EmOtiOnAL FUeL | | I told mah domestic help the other day ....
"Ja-Pan le aah"..
And he started asking for the flight ticket !
Private Reply to EmOtiOnAL FUeL |
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