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| Dec 18, 2006 10:00 am |
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re: re: re: re: Riddle |
H.K.L. Sachdeva
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Dear Sumanth,
I am fully with you about Probability being a fraction between
0 & 1 because being a Mathematics Graduate myself, I fully
well know that the Probability has to be a fraction of the total
number of possible combinations (for a particular condition)
and the total number of combinations as a whole.
But I was not talking of probability, I was talking of the
possible number of combinations in which 6th, 8th & 12th
house will not be occupied by any planet and that has to
be a whole number.
And whether we calculate the Possible Number of Combinations
or the Probability, we have to keep in mind the positioning of
Rahu & Ketu which always occupy the opposite houses and for
them we have to exclude them in four houses (and not three
as in the case of ther planets) i.e. 2nd, 6th, 8th & 12th house.
That means, for 7 Planets we have to calculate separately
and for the remaining two (counting them as one only
becuase when Rahu is any of the houses 1 to 6, Ketu is in
the houses 7 to 12 respectively and vice versa) we have to
calculate separately. And while the exclusion for the 7
Planets is for three house, it has to be for four houses
for Rahu & Ketu.
I think, it would be more appropriate to recalculate the
probability or the number of combinations in the light of
the foregoing.
H.K.L. Sachdeva Private Reply to H.K.L. Sachdeva (new win) |
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