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The Man in the Bar.... a riddle!

Dec 20, 2006 9:36 am

re: re: re: re: re: re: Riddle

H.K.L. Sachdeva

Dear Sumanth,

I think, going by your analogy, the possible number of
combinations of seven planets' (other than Rahu & Ketu)
occupying nine out twelve houses will be :-

9 x 9 x 9 x 9 x 9 x 9 x 9 = 47,82,969

out of a total number of

12 x 12 x 12 x 12 x 12 x 12 x 12 = 3,58,31,808

combinations

and

the possible number of combinations for one planet (taking
Rahu & Ketu as one) occupying eight out of twelve houses,
singly, will be :-

8 out of 12

and when we combine it with the combinations of the other
seven planets, the total number of combinations should be :-

9 x 9 x 9 x 9 x 9 x 9 x 9 x 8 = 3,82,63,752

out of a total number of

12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 = 42,99,81,696

thereby giving a probability of

0.088989.

H.K.L. Sachdeva

Private Reply to H.K.L. Sachdeva (new win)

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